http://www.elsanglin.com/forums/topic/fish-math Discussion about fishing in World of Warcraft. en-US Sat, 20 Mar 2010 13:47:44 +0000 http://bbpress.org/?v=1.0.2 q http://www.elsanglin.com/forums/search.php http://www.elsanglin.com/forums/topic/fish-math#post-6374 Thu, 28 May 2009 19:14:13 +0000 donquixote235 6374@http://www.elsanglin.com/forums/ <p>In other words... you'll get more throws but less catches. I personally would favor the reverse ;)</p> <p>Not to mention the fact that the first ten seconds of a cast will NEVER yield a fish. In the 14-second recast scenario, if you recast the line you'll have to wait at least ten seconds for a chance to catch, whereas if you'd just stick it out for the remaining six seconds you'd be guaranteed to get a bite. </p> http://www.elsanglin.com/forums/topic/fish-math#post-6372 Thu, 28 May 2009 10:38:06 +0000 Arutha 6372@http://www.elsanglin.com/forums/ <p>oh thats a topic for me xD</p> <p>So Blizzard has made every catch a 100% chance to pull something out of the depths of the sea.<br /> I think the only way to realize this is to increase the chance of catching the fish every 0.1sec or so...<br /> Stop me if I'm wrong.... too late, you had your time :P</p> <p>so we have the first formula: <code>[percentage of hooking fish] = ( [time passed by] / [full time to fish]) * 100</code></p> <p>lets assume [full time to fish] = 20s - 1s(reaction time) -1s (lag) = 18s;</p> <p>so we have <code>f(x) = (x / 18) * 100</code><br /> At the exact 14th second one has a 77.78% chance to catch a fish.</p> <p>The next thing to think about is that the <code>[percentage of hooking fish WITHIN a time x] (short: p(x) )</code>is totally different to the [percentage of hooking fish]. </p> <p>turn f(x) from seconds into tenths of seconds: f(x) = (x*10 / 180) *100</p> <p><code>p(x) = (sum from i = 0 to x over f(i) ) / ( sum from i = 0 to 180 over f(i) )</code></p> <p>so the chance, that one has caught a fish WITHIN the first 14s is just 60.4% .<br /> This is not very much, is it?</p> <p>according to the authors post:<br /> yes, you could save 6s and make 400 throws instead of 300, but in these 400 throws you would just have approximately 400*0.604 = 241.6 fishes instead of 300 save fishes...</p> <p>q.e.d. :P </p> http://www.elsanglin.com/forums/topic/fish-math#post-6359 Wed, 27 May 2009 00:27:53 +0000 Leny 6359@http://www.elsanglin.com/forums/ <p>I think I "Kinda" under stand it, hes trying to say that it COULD increase catching speed because it could pop up early in the next cast, thus increasing speed. But, it could compleatly backfire upon you and it would be at the end on the secound cast. Over all id stay with the "old fashion" way of just waiting on it. </p> http://www.elsanglin.com/forums/topic/fish-math#post-6356 Tue, 26 May 2009 17:47:53 +0000 Grank 6356@http://www.elsanglin.com/forums/ <p>I think another way to look at this is: if you have hit the 14 second mark you are guaranteed to get a strike within 6 seconds, whereas if you recast you reset the countdown to another possible 14 second wait (assuming you will recast at that time if you reach it). I'd just hang on for the next 6 seconds, since that is a relatively fast time to hook a fish.</p> <p>- or- </p> <p>If I reread El's post I can see that I've said pretty much the same thing :) </p> http://www.elsanglin.com/forums/topic/fish-math#post-6352 Mon, 25 May 2009 22:06:41 +0000 el 6352@http://www.elsanglin.com/forums/ <p>I don't follow the logic: You wait 14 seconds, and then abandon the cast. Yet an extra 6 seconds of fishing would have guaranteed that catch. So your next cast would always have to catch a fish in under 6 seconds for this to be "faster" overall. Surely this only makes sense is there is a greater chance of catching a fish in the first 10 seconds? And even then you would need to factor in lag/latency and "misses" when pool fishing. </p> http://www.elsanglin.com/forums/topic/fish-math#post-6351 Mon, 25 May 2009 21:16:51 +0000 beerforme 6351@http://www.elsanglin.com/forums/ <p>Just a quick one that I haven't seen posted on here or any other site. Tourney and Turtle scenario only. Other fish I am not worrried about.... But I still want to catch them :) .</p> <p>My math uses the basic method of 7 and 14 second for the bobber movement. I know these number aren't correct, but for the simple math here they will work.</p> <p>If I am casting to catch fish and wiat the full 20 seconds = 100% of catching something.</p> <p>if I wait til after about 14 second and nothing, I Cast again. This saves me about 6 seconds.</p> <p>The math is ...which way is better after say 300 casts. I know that I am getting 1 extra cast per minute with the remaining 6 second x 3 casts.</p> <p>regular = 60 seconds = full wait 20 seconds = 3 casts<br /> speed = 60 seconds = 2/3 wait ~ 14 seconds = 4.2857 casts</p> <p>In this "casting time" I get either 300 casts IF ALL casts hit on the "20 second" mark or just over 400 if I use the "speed fishing" .</p> <p>The question now becomes is it worth the extra casts to know in the back of your mind that you may have "wasted" the cast in not getting the tasty fish/turtle. </p>